
This year's cosine function!
Posted: Posted January 19th Edited January 19th by The Fly
 And here's one that I don't know how to solve! (Granted haven't spent much time on it.)
Find the product
\( \cos(x) \cos(2x) \cos(3x) \cdots \cos(2017x) \)
where \( x = \displaystyle\frac{2\pi}{2018} \).
(That's from the same Math Wrangle exam.) ... Weird Problems!
Have fun!
The Fly
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